What is expand 1/((z-1)^2(z-3)) ?

The solution to expand 1/((z-1)^2(z-3)) is 1/(z^3-5z^2+7z-3)

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expand 1/((z-1)^2(z-3))

expand

\frac{1}{( z - 1 ) ^{2} ( z - 3 )}

\frac{1}{z ^{3} - 5 z ^{2} + 7 z - 3}

Solution steps

\frac{1}{( z - 1 ) ^{2} ( z - 3 )}

(z - 1)^{2} = z^{2} - 2 z + 1

= \frac{1}{( z ^{2} - 2 z + 1 ) ( z - 3 )}

Expand

(z^{2} - 2 z + 1) (z - 3) : z^{3} - 5 z^{2} + 7 z - 3

= \frac{1}{z ^{3} - 5 z ^{2} + 7 z - 3}

\frac{1}{x ( 1 - ln ( x ) )}

\frac{ka + a + kb}{k ( k + 1 )}

(t^{4} + 2) e^{2 t}

2 π (7 x^{4} - 28 x^{3} + 28 x^{2})

\frac{v ( v - 1 )}{2} - e

What is expand 1/((z-1)^2(z-3)) ?
The solution to expand 1/((z-1)^2(z-3)) is 1/(z^3-5z^2+7z-3)