What is expand (x^2-2x-3)/((x^2-x+4)^2) ?

The solution to expand (x^2-2x-3)/((x^2-x+4)^2) is (x^2-2x-3)/(x^4-2x^3+9x^2-8x+16)

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expand (x^2-2x-3)/((x^2-x+4)^2)

expand

\frac{x ^{2} - 2 x - 3}{( x ^{2} - x + 4 ) ^{2}}

\frac{x ^{2} - 2 x - 3}{x ^{4} - 2 x ^{3} + 9 x ^{2} - 8 x + 16}

Solution steps

\frac{x ^{2} - 2 x - 3}{( x ^{2} - x + 4 ) ^{2}}

(x^{2} - x + 4)^{2} = x^{4} - 2 x^{3} + 9 x^{2} - 8 x + 16

= \frac{x ^{2} - 2 x - 3}{x ^{4} - 2 x ^{3} + 9 x ^{2} - 8 x + 16}

2 ((1 + π^{2})^{\frac{3}{2}} - 1)

\frac{( s ^{2} + 4 s - 2 )}{( s - 2 ) ( s ^{2} + 5 s - 5 )}

(2 t - e^{3 t})^{2}

\frac{( 2 - x ) \cdot n}{x}

(cos (2 π x) + i sin (2 π x))^{3}

What is expand (x^2-2x-3)/((x^2-x+4)^2) ?
The solution to expand (x^2-2x-3)/((x^2-x+4)^2) is (x^2-2x-3)/(x^4-2x^3+9x^2-8x+16)