What is expand (e+s+k-2c)(e+s+k-2c) ?

The solution to expand (e+s+k-2c)(e+s+k-2c) is 2es-4cs+2ks+s^2+e^2-4ec+4c^2+2ek+k^2-4ck

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expand (e+s+k-2c)(e+s+k-2c)

expand

(e + s + k - 2 c) (e + s + k - 2 c)

2 es - 4 cs + 2 k s + s^{2} + e^{2} - 4 ec + 4 c^{2} + 2 e k + k^{2} - 4 c k

Solution steps

(e + s + k - 2 c) (e + s + k - 2 c)

Distribute parentheses

= ee + es + e k + e (- 2 c) + se + ss + s k + s (- 2 c) + k e + k s + kk + k (- 2 c) + (- 2 c) e + (- 2 c) s + (- 2 c) k + (- 2 c) (- 2 c)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= ee + es + e k - 2 ec + es + ss + k s - 2 cs + e k + k s + kk - 2 c k - 2 ec - 2 cs - 2 c k + 2 \cdot 2 cc

Simplify

ee + es + e k - 2 ec + es + ss + k s - 2 cs + e k + k s + kk - 2 c k - 2 ec - 2 cs - 2 c k + 2 \cdot 2 cc : 2 es - 4 cs + 2 k s + s^{2} + e^{2} - 4 ec + 4 c^{2} + 2 e k + k^{2} - 4 c k

= 2 es - 4 cs + 2 k s + s^{2} + e^{2} - 4 ec + 4 c^{2} + 2 e k + k^{2} - 4 c k

\frac{tan ( x ) ( 3 - tan ^{2} ( x ) )}{1 - 3 tan ^{2} ( x )}

\frac{1}{( ( x ^{2} - 2 \cdot x + 2 ) \cdot x )}

- \frac{x ^{2} - 6 x + 21}{( x ^{2} - 3 ) ( x + 4 )}

\frac{252037 ( x ^{2} - 46 x + 577 )}{365 ( x - 23 ) ^{2}}

\frac{2 s ^{2} + 1}{s ^{2} ( s + 2 )}

What is expand (e+s+k-2c)(e+s+k-2c) ?
The solution to expand (e+s+k-2c)(e+s+k-2c) is 2es-4cs+2ks+s^2+e^2-4ec+4c^2+2ek+k^2-4ck