What is expand ((4x+1)(x-5))/(x-4) ?

The solution to expand ((4x+1)(x-5))/(x-4) is (4x^2-19x-5)/(x-4)

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expand ((4x+1)(x-5))/(x-4)

expand

\frac{( 4 x + 1 ) ( x - 5 )}{x - 4}

\frac{4 x ^{2} - 19 x - 5}{x - 4}

Solution steps

\frac{( 4 x + 1 ) ( x - 5 )}{x - 4}

Expand

(4 x + 1) (x - 5) : 4 x^{2} - 19 x - 5

= \frac{4 x ^{2} - 19 x - 5}{x - 4}

\frac{x ^{2} + 7 x + 2}{( x ^{2} - 6 x + 13 ) x}

- \frac{4 x ^{3}}{( x ^{2} + 4 ) ^{2}}

\frac{3 x + 5}{3 ( 3 x + 9 )}

\frac{1 + cosh ( x ) sinh ( x ) + ( sinh ( x ) ) ^{2}}{e ^{x}}

- \frac{d}{d x} (150 (120 - x)^{2})

What is expand ((4x+1)(x-5))/(x-4) ?
The solution to expand ((4x+1)(x-5))/(x-4) is (4x^2-19x-5)/(x-4)