展开 1/((x+4)(x-3))

解答

展开

\frac{1}{( x + 4 ) ( x - 3 )}

\frac{1}{x ^{2} + x - 12}

求解步骤

\frac{1}{( x + 4 ) ( x - 3 )}

乘开

(x + 4) (x - 3) : x^{2} + x - 12

= \frac{1}{x ^{2} + x - 12}

e x p an d \frac{sec ^{2} ( \frac{x}{2} )}{tan ( \frac{x}{2} )}

e x p an d \frac{2 x ( 6 - 2 x ) ^{3}}{81}

\frac{d}{d t} ((t) (k (100 - t)))

e x p an d \frac{7}{( x - 1 ) ( x - 8 )}

e x p an d x + (e^{x} - 2)^{2}