What is expand (x((2x+5)^{3/2}-(-2x+5)^{3/2}))/3 ?

The solution to expand (x((2x+5)^{3/2}-(-2x+5)^{3/2}))/3 is (x(2x+5)^{3/2})/3-(x(-2x+5)^{3/2})/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x((2x+5)^{3/2}-(-2x+5)^{3/2}))/3

expand

\frac{x ( ( 2 x + 5 ) ^{\frac{3}{2}} - ( - 2 x + 5 ) ^{\frac{3}{2}} )}{3}

\frac{x ( 2 x + 5 ) ^{\frac{3}{2}}}{3} - \frac{x ( - 2 x + 5 ) ^{\frac{3}{2}}}{3}

Solution steps

\frac{x ( ( 2 x + 5 ) ^{\frac{3}{2}} - ( - 2 x + 5 ) ^{\frac{3}{2}} )}{3}

Expand

x ((2 x + 5)^{\frac{3}{2}} - (- 2 x + 5)^{\frac{3}{2}}) : x (2 x + 5)^{\frac{3}{2}} - x (- 2 x + 5)^{\frac{3}{2}}

= \frac{x ( 2 x + 5 ) ^{\frac{3}{2}} - x ( - 2 x + 5 ) ^{\frac{3}{2}}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ( 2 x + 5 ) ^{\frac{3}{2}} - x ( - 2 x + 5 ) ^{\frac{3}{2}}}{3} = \frac{x ( 2 x + 5 ) ^{\frac{3}{2}}}{3} - \frac{x ( - 2 x + 5 ) ^{\frac{3}{2}}}{3}

= \frac{x ( 2 x + 5 ) ^{\frac{3}{2}}}{3} - \frac{x ( - 2 x + 5 ) ^{\frac{3}{2}}}{3}

\frac{4}{( s + 3 ) ^{2} ( s ^{2} + 7 s + 10 )}

\frac{1}{( x - 3 ) ( x + 2 )}

1 - \frac{14 ( 0.02 x + 1 )}{x ^{3} + 25 x ^{2} + 84.28 x + 14}

\frac{x + 2}{( x + 1 ) ^{2}}

\frac{( x ^{7} + 4 ) ^{7}}{128 x ^{14}}

What is expand (x((2x+5)^{3/2}-(-2x+5)^{3/2}))/3 ?
The solution to expand (x((2x+5)^{3/2}-(-2x+5)^{3/2}))/3 is (x(2x+5)^{3/2})/3-(x(-2x+5)^{3/2})/3