What is expand ((-1+2p)^{-1+n}-1)/(ln(-1+2p)) ?

The solution to expand ((-1+2p)^{-1+n}-1)/(ln(-1+2p)) is ((-1+2p)^{-1+n})/(ln(-1+2p))-1/(ln(-1+2p))

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expand ((-1+2p)^{-1+n}-1)/(ln(-1+2p))

expand

\frac{( - 1 + 2 p ) ^{- 1 + n} - 1}{ln ( - 1 + 2 p )}

\frac{( - 1 + 2 p ) ^{- 1 + n}}{ln ( - 1 + 2 p )} - \frac{1}{ln ( - 1 + 2 p )}

Solution steps

\frac{( - 1 + 2 p ) ^{- 1 + n} - 1}{ln ( - 1 + 2 p )}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{( - 1 + 2 p ) ^{- 1 + n} - 1}{ln ( - 1 + 2 p )} = \frac{( - 1 + 2 p ) ^{- 1 + n}}{ln ( - 1 + 2 p )} - \frac{1}{ln ( - 1 + 2 p )}

= \frac{( 2 p - 1 ) ^{n - 1}}{ln ( 2 p - 1 )} - \frac{1}{ln ( 2 p - 1 )}

\frac{k s + 8 k + s m}{s ( s + 8 )}

(10 - 20 e^{- 12 t})^{2}

\frac{2 x ^{2} + 4 x + 8}{( x + 2 ) ( x ^{2} + x + 6 )}

(3 + y + 2 y^{2})^{5}

(3 + 7 e^{- 0.25 x})^{2}

What is expand ((-1+2p)^{-1+n}-1)/(ln(-1+2p)) ?
The solution to expand ((-1+2p)^{-1+n}-1)/(ln(-1+2p)) is ((-1+2p)^{-1+n})/(ln(-1+2p))-1/(ln(-1+2p))