What is expand (2xe^y+e^y)dx+(x^2+1)e^ydy ?

The solution to expand (2xe^y+e^y)dx+(x^2+1)e^ydy is 2e^yxdx+e^ydx+e^yx^2dy+e^ydy

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expand (2xe^y+e^y)dx+(x^2+1)e^ydy

expand

(2 x e^{y} + e^{y}) d x + (x^{2} + 1) e^{y} d y

2 e^{y} x d x + e^{y} d x + e^{y} x^{2} d y + e^{y} d y

Solution steps

(2 x e^{y} + e^{y}) d x + (x^{2} + 1) e^{y} d y

= (2 e^{y} x + e^{y}) d x + e^{y} (x^{2} + 1) d y

Expand

d x (2 x e^{y} + e^{y}) : 2 e^{y} x d x + e^{y} d x

= 2 e^{y} x d x + e^{y} d x + (x^{2} + 1) e^{y} d y

Expand

e^{y} d y (x^{2} + 1) : e^{y} x^{2} d y + e^{y} d y

= 2 e^{y} x d x + e^{y} d x + e^{y} x^{2} d y + e^{y} d y

\frac{2}{s ( s + 2 ) ( s + 10 )}

(x^{2 - \frac{2}{x}})^{9}

\frac{3}{2} (e^{x} - \frac{1}{9} (e^{3 x} \cdot 3 x - e^{3 x}) + C)

- (\frac{5}{14} lo g_{2} (\frac{5}{14}) + \frac{9}{14} lo g_{2} (\frac{9}{14}))

x - 2

What is expand (2xe^y+e^y)dx+(x^2+1)e^ydy ?
The solution to expand (2xe^y+e^y)dx+(x^2+1)e^ydy is 2e^yxdx+e^ydx+e^yx^2dy+e^ydy