What is expand (7x^2-7x-14)/((2x-1)(x^2-x-5)) ?

The solution to expand (7x^2-7x-14)/((2x-1)(x^2-x-5)) is (7x^2-7x-14)/(2x^3-3x^2-9x+5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (7x^2-7x-14)/((2x-1)(x^2-x-5))

expand

\frac{7 x ^{2} - 7 x - 14}{( 2 x - 1 ) ( x ^{2} - x - 5 )}

\frac{7 x ^{2} - 7 x - 14}{2 x ^{3} - 3 x ^{2} - 9 x + 5}

Solution steps

\frac{7 x ^{2} - 7 x - 14}{( 2 x - 1 ) ( x ^{2} - x - 5 )}

Expand

(2 x - 1) (x^{2} - x - 5) : 2 x^{3} - 3 x^{2} - 9 x + 5

= \frac{7 x ^{2} - 7 x - 14}{2 x ^{3} - 3 x ^{2} - 9 x + 5}

\frac{3 x + 5}{( 8 x + 2 ) ( x - 4 )}

(b^{2} e^{b t} sin (t) + b e^{b t} cos (t))^{2}

(2 x^{2} - y^{2}) d x + (x y) d y

\frac{- 15 x ^{2} + 495 x - 1350}{2}

\frac{( x + 2 ) ( x + 3 )}{( x - 2 ) ( x - 3 )}

What is expand (7x^2-7x-14)/((2x-1)(x^2-x-5)) ?
The solution to expand (7x^2-7x-14)/((2x-1)(x^2-x-5)) is (7x^2-7x-14)/(2x^3-3x^2-9x+5)