What is expand 2y(y^2-5y-3)+y(y+1)' ?

The solution to expand 2y(y^2-5y-3)+y(y+1)' is 2y^3-10y^2-6y+y(y+1)'

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expand 2y(y^2-5y-3)+y(y+1)'

expand

2 y (y^{2} - 5 y - 3) + y (y + 1)^{'}

2 y^{3} - 10 y^{2} - 6 y + y (y + 1)'

Solution steps

2 y (y^{2} - 5 y - 3) + y (y + 1)^{'}

Expand

2 y (y^{2} - 5 y - 3) : 2 y^{3} - 10 y^{2} - 6 y

= 2 y^{3} - 10 y^{2} - 6 y + y (y + 1)^{'}

- 2^{3}

sin (x) (- ln (cos (x))) + cos (x) (- x + tan (x))

\frac{( x - 8 ) ( x + 3 )}{( x + 9 ) ( x - 1 )}

(y^{3} + 10 x y^{4} - 2 x) d x + (3 x y^{2} + 20 x^{2} y^{3}) d y

\frac{( x ^{3} + x ) ^{10}}{10}

What is expand 2y(y^2-5y-3)+y(y+1)' ?
The solution to expand 2y(y^2-5y-3)+y(y+1)' is 2y^3-10y^2-6y+y(y+1)'