What is expand (x^2+cx+1)(x^2+dx+1) ?

The solution to expand (x^2+cx+1)(x^2+dx+1) is cx^3+x^4+x^2dx+2x^2+cxdx+cx+dx+1

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expand (x^2+cx+1)(x^2+dx+1)

expand

(x^{2} + c x + 1) (x^{2} + d x + 1)

c x^{3} + x^{4} + x^{2} d x + 2 x^{2} + c x d x + c x + d x + 1

Solution steps

(x^{2} + c x + 1) (x^{2} + d x + 1)

Distribute parentheses

= x^{2} x^{2} + x^{2} d x + x^{2} \cdot 1 + c x x^{2} + c x d x + c x \cdot 1 + 1 \cdot x^{2} + 1 \cdot d x + 1 \cdot 1

= x^{2} x^{2} + x^{2} d x + 1 \cdot x^{2} + c x^{2} x + c x d x + 1 \cdot c x + 1 \cdot x^{2} + 1 \cdot d x + 1 \cdot 1

Simplify

x^{2} x^{2} + x^{2} d x + 1 \cdot x^{2} + c x^{2} x + c x d x + 1 \cdot c x + 1 \cdot x^{2} + 1 \cdot d x + 1 \cdot 1 : c x^{3} + x^{4} + x^{2} d x + 2 x^{2} + c x d x + c x + d x + 1

= c x^{3} + x^{4} + x^{2} d x + 2 x^{2} + c x d x + c x + d x + 1

8 (5 x + 8 y = - 24)

\frac{x ( 2 x + 3 )}{2 x + 1}

x (ln (x + 1) (x + 1) - x)

(z = 6, + 9 i) - (w (z) = 3 - 5 i)

\frac{12 C + ( 4 x ^{2} - 5 ) ^{\frac{3}{2}}}{12}

What is expand (x^2+cx+1)(x^2+dx+1) ?
The solution to expand (x^2+cx+1)(x^2+dx+1) is cx^3+x^4+x^2dx+2x^2+cxdx+cx+dx+1