What is expand (1-cos(x))ln(1+x^2) ?

The solution to expand (1-cos(x))ln(1+x^2) is ln(1+x^2)-ln(1+x^2)cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (1-cos(x))ln(1+x^2)

expand

(1 - cos (x)) ln (1 + x^{2})

ln (1 + x^{2}) - ln (1 + x^{2}) cos (x)

Solution steps

(1 - cos (x)) ln (1 + x^{2})

= ln (1 + x^{2}) (1 - cos (x))

Apply the distributive law:

a (b - c) = ab - a c

a = ln (1 + x^{2}), b = 1, c = cos (x)

= ln (1 + x^{2}) \cdot 1 - ln (1 + x^{2}) cos (x)

= 1 \cdot ln (1 + x^{2}) - ln (1 + x^{2}) cos (x)

Multiply:

1 \cdot ln (1 + x^{2}) = ln (1 + x^{2})

= ln (1 + x^{2}) - ln (1 + x^{2}) cos (x)

\frac{( 9 + x ^{2} ) ^{11}}{177147 x ^{11}}

\frac{( 2 t + 1 ) ( t + 2 )}{2}

\frac{2 ( 2 x + z ) + y}{4}

(lo g_{10} (x) - \frac{1}{ln ^{2} ( 2 x )})^{3}

\frac{e ^{- s - 1} + 4}{( s + 5 ) ( s + 1 )}

What is expand (1-cos(x))ln(1+x^2) ?
The solution to expand (1-cos(x))ln(1+x^2) is ln(1+x^2)-ln(1+x^2)cos(x)