What is expand (2s+3)/((s-1)(2s+1)(s+2)(s+1)) ?

The solution to expand (2s+3)/((s-1)(2s+1)(s+2)(s+1)) is (2s+3)/(2s^4+5s^3-5s-2)

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expand (2s+3)/((s-1)(2s+1)(s+2)(s+1))

expand

\frac{2 s + 3}{( s - 1 ) ( 2 s + 1 ) ( s + 2 ) ( s + 1 )}

\frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 5 s - 2}

Solution steps

\frac{2 s + 3}{( s - 1 ) ( 2 s + 1 ) ( s + 2 ) ( s + 1 )}

Expand

(s - 1) (2 s + 1) (s + 2) (s + 1) : 2 s^{4} + 5 s^{3} - 5 s - 2

= \frac{2 s + 3}{2 s ^{4} + 5 s ^{3} - 5 s - 2}

(x - (e^{2} + 1))^{2}

\frac{2 e ^{- 3 s} - 2 e ^{- 4 s}}{s ( s ^{2} + 6 s + 34 )}

e^{y} \cdot (1 + x^{2}) \cdot d y - 2 x (1 + e^{y}) d x

[sin (\frac{( 2 n - 1 ) π}{2})]^{n - 1}

[(s + 1) (s^{2} + 4 s + 8)]^{^{'}}

What is expand (2s+3)/((s-1)(2s+1)(s+2)(s+1)) ?
The solution to expand (2s+3)/((s-1)(2s+1)(s+2)(s+1)) is (2s+3)/(2s^4+5s^3-5s-2)