What is (0.04)/(s^3(s^2+0.04))-(25)/(s^2+0.04) ?

The solution to (0.04)/(s^3(s^2+0.04))-(25)/(s^2+0.04) is 1/(25s^3(s^2+0.04))-(25)/(s^2+0.04)

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simplify (0.04)/(s^3(s^2+0.04))-(25)/(s^2+0.04)

simplify

\frac{0.04}{s ^{3} ( s ^{2} + 0.04 )} - \frac{25}{s ^{2} + 0.04}

\frac{1}{25 s ^{3} ( s ^{2} + 0.04 )} - \frac{25}{s ^{2} + 0.04}

Solution steps

\frac{0.04}{s ^{3} ( s ^{2} + 0.04 )} - \frac{25}{s ^{2} + 0.04}

Simplify

\frac{0.04}{s ^{3} ( s ^{2} + 0.04 )} : \frac{4}{100 s ^{3} ( s ^{2} + 0.04 )}

= \frac{4}{100 s ^{3} ( s ^{2} + 0.04 )} - \frac{25}{s ^{2} + 0.04}

Cancel

\frac{4}{100} : \frac{1}{25}

= \frac{1}{25 s ^{3} ( s ^{2} + 0.04 )} - \frac{25}{s ^{2} + 0.04}

h (h + 1 - h = \frac{1}{2})

\frac{3 x - 1}{3 ( x - 1 )}

\frac{1}{( u - 1 ) ( u + 3 )}

π (a h^{2} - \frac{h ^{3}}{3})

What is (0.04)/(s^3(s^2+0.04))-(25)/(s^2+0.04) ?
The solution to (0.04)/(s^3(s^2+0.04))-(25)/(s^2+0.04) is 1/(25s^3(s^2+0.04))-(25)/(s^2+0.04)