What is expand 1/((x-1)(x^2-x+1)) ?

The solution to expand 1/((x-1)(x^2-x+1)) is 1/(x^3-2x^2+2x-1)

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expand 1/((x-1)(x^2-x+1))

expand

\frac{1}{( x - 1 ) ( x ^{2} - x + 1 )}

\frac{1}{x ^{3} - 2 x ^{2} + 2 x - 1}

Solution steps

\frac{1}{( x - 1 ) ( x ^{2} - x + 1 )}

Expand

(x - 1) (x^{2} - x + 1) : x^{3} - 2 x^{2} + 2 x - 1

= \frac{1}{x ^{3} - 2 x ^{2} + 2 x - 1}

\frac{s - 1}{( x + 1 ) ^{2} ( x - 2 )}

(e^{x} + 4)^{2}

8 - \frac{1}{2} 0

a sin (e) (b x + c) + d

\frac{3 x ^{2}}{36} + \frac{( 8 - x ) ^{2}}{4 π}

What is expand 1/((x-1)(x^2-x+1)) ?
The solution to expand 1/((x-1)(x^2-x+1)) is 1/(x^3-2x^2+2x-1)