What is expand 1/(4(x^2+x+3)^4) ?

The solution to expand 1/(4(x^2+x+3)^4) is 1/(4x^8+16x^7+72x^6+160x^5+364x^4+480x^3+648x^2+432x+324)

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expand 1/(4(x^2+x+3)^4)

expand

\frac{1}{4 ( x ^{2} + x + 3 ) ^{4}}

\frac{1}{4 x ^{8} + 16 x ^{7} + 72 x ^{6} + 160 x ^{5} + 364 x ^{4} + 480 x ^{3} + 648 x ^{2} + 432 x + 324}

Solution steps

\frac{1}{4 ( x ^{2} + x + 3 ) ^{4}}

(x^{2} + x + 3)^{4} = x^{8} + 4 x^{7} + 18 x^{6} + 40 x^{5} + 91 x^{4} + 120 x^{3} + 162 x^{2} + 108 x + 81

= \frac{1}{4 ( x ^{8} + 4 x ^{7} + 18 x ^{6} + 40 x ^{5} + 91 x ^{4} + 120 x ^{3} + 162 x ^{2} + 108 x + 81 )}

Expand

4 (x^{8} + 4 x^{7} + 18 x^{6} + 40 x^{5} + 91 x^{4} + 120 x^{3} + 162 x^{2} + 108 x + 81) : 4 x^{8} + 16 x^{7} + 72 x^{6} + 160 x^{5} + 364 x^{4} + 480 x^{3} + 648 x^{2} + 432 x + 324

= \frac{1}{4 x ^{8} + 16 x ^{7} + 72 x ^{6} + 160 x ^{5} + 364 x ^{4} + 480 x ^{3} + 648 x ^{2} + 432 x + 324}

\frac{35}{6 d ^{2} ( 18 d ^{2} - 11 d + 1 )}

\frac{- s - 2}{( s + 1 ) ( s + 4 )}

(6 x^{5} - 4 x^{3} + 2 x) d x

\frac{3 x + 7}{( x - 1 ) ( x - 2 )}

\frac{( 50 - ln ( 5 ) ) ( 375 - 5 )}{140620}

What is expand 1/(4(x^2+x+3)^4) ?
The solution to expand 1/(4(x^2+x+3)^4) is 1/(4x^8+16x^7+72x^6+160x^5+364x^4+480x^3+648x^2+432x+324)