What is expand f'(2)(5+|x-2|) ?

The solution to expand f'(2)(5+|x-2|) is 5f'(2)+|x-2|f'(2)

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expand f'(2)(5+|x-2|)

expand

f^{'} (2) (5 + ∣ x - 2 ∣)

5 f' (2) + ∣ x - 2 ∣ f' (2)

Solution steps

f^{'} (2) (5 + ∣ x - 2 ∣)

Apply the distributive law:

a (b + c) = ab + a c

a = f^{'} (2), b = 5, c = ∣ x - 2 ∣

= f^{^{'}} (2) 5 + f^{^{'}} (2) ∣ x - 2 ∣

= 5 f^{^{'}} (2) + ∣ x - 2 ∣ f^{^{'}} (2)

δ, (x - 2)

π (x)^{2} (3 x + 1)

x \cdot x^{2}

(z - e^{i \frac{π}{4}}) (z - e^{- i \frac{π}{4}})

k + (2 (l - k) + 1)^{\frac{1}{2}} - 1

What is expand f'(2)(5+|x-2|) ?
The solution to expand f'(2)(5+|x-2|) is 5f'(2)+|x-2|f'(2)