What is 4>= sqrt(6x-12)-8 ?

The solution to 4>= sqrt(6x-12)-8 is 2<= x<= 26

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4>= sqrt(6x-12)-8

4 \geq 6 x - 12 - 8

2 \leq x \leq 26

Solution steps

4 \geq 6 x - 12 - 8

Switch sides

6 x - 12 - 8 \leq 4

Move

8

to the right side

6 x - 12 \leq 12

Square both sides

(6 x - 12)^{2} \leq 1 2^{2}

Simplify

6 x - 12 \leq 144

6 x - 12 \leq 144 : x \leq 26

x \leq 26

Find singularity points

Find non-negative values for radicals:

x \geq 2

Combine the intervals

x \leq 26 and x \geq 2

Merge Overlapping Intervals

2 \leq x \leq 26

3 y^{2} - 27 y = 0

(1 + \frac{0.052}{12})^{12} - 1

- 3 = \frac{4}{3} x

\frac{365}{180} \frac{100000 - 95400}{95400}

(\frac{1}{80} + \frac{1}{20})^{- 1}