What is expand 2((x+2)^2=-24+x(3(x-3)-2(x-1))) ?

The solution to expand 2((x+2)^2=-24+x(3(x-3)-2(x-1))) is 2x^2+8x+8=2x^2-14x-48

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expand 2((x+2)^2=-24+x(3(x-3)-2(x-1)))

expand

2 ((x + 2)^{2} = - 24 + x (3 (x - 3) - 2 (x - 1)))

2 x^{2} + 8 x + 8 = 2 x^{2} - 14 x - 48

Solution steps

2 ((x + 2)^{2} = - 24 + x (3 (x - 3) - 2 (x - 1)))

= 2 (= (x + 2)^{2} - 24 + x (3 (x - 3) - 2 (x - 1)))

Distribute parentheses

2 (x + 2)^{2} = 2 (- 24) + 2 x (3 (x - 3) - 2 (x - 1))

Apply minus-plus rules

+ (- a) = - a

2 (x + 2)^{2} = - 2 \cdot 24 + 2 x (3 (x - 3) - 2 (x - 1))

Simplify

2 (x + 2)^{2} = - 2 \cdot 24 + 2 x (3 (x - 3) - 2 (x - 1)) : 2 x^{2} + 8 x + 8 = 2 x^{2} - 14 x - 48

2 x^{2} + 8 x + 8 = 2 x^{2} - 14 x - 48

(y = x + 4,) (, y = - 2 x - 2)

π (ln (108) - 2)

(- e^{x} + e^{- x}) (π e^{x - 1} - e^{x - 2} - e^{- x})

10 c + 10 - (\frac{( 100 ( 2 c - 8 ) )}{c ^{2} - 8 c + 20})

\frac{3 x ^{2} y ^{2}}{4 ( x ^{3} y - 3 )}

What is expand 2((x+2)^2=-24+x(3(x-3)-2(x-1))) ?
The solution to expand 2((x+2)^2=-24+x(3(x-3)-2(x-1))) is 2x^2+8x+8=2x^2-14x-48