What is expand 1/2 (e^{4t}+e^{-2t})(6t+1) ?

The solution to expand 1/2 (e^{4t}+e^{-2t})(6t+1) is 3e^{4t}t+1/2 e^{4t}+3e^{-2t}t+1/2 e^{-2t}

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expand 1/2 (e^{4t}+e^{-2t})(6t+1)

expand

\frac{1}{2} (e^{4 t} + e^{- 2 t}) (6 t + 1)

3 e^{4 t} t + \frac{1}{2} e^{4 t} + 3 e^{- 2 t} t + \frac{1}{2} e^{- 2 t}

Solution steps

\frac{1}{2} (e^{4 t} + e^{- 2 t}) (6 t + 1)

Expand

(e^{4 t} + e^{- 2 t}) (6 t + 1) : 6 e^{4 t} t + e^{4 t} + 6 e^{- 2 t} t + e^{- 2 t}

= \frac{1}{2} (6 e^{4 t} t + e^{4 t} + 6 e^{- 2 t} t + e^{- 2 t})

Expand

\frac{1}{2} (6 e^{4 t} t + e^{4 t} + 6 e^{- 2 t} t + e^{- 2 t}) : 3 e^{4 t} t + \frac{1}{2} e^{4 t} + 3 e^{- 2 t} t + \frac{1}{2} e^{- 2 t}

= 3 e^{4 t} t + \frac{1}{2} e^{4 t} + 3 e^{- 2 t} t + \frac{1}{2} e^{- 2 t}

\frac{1}{( 2 s + 1 ) ^{2} ( s - j w )}

(\frac{4 t + 2}{t} + t + 2 t^{3}) (e^{4 t} + t^{3} + 4 e^{2 t})

(2 x y^{2} + 2 y) d x

\frac{2 x ( - 2 x + 6 ) ^{3}}{81}

\frac{\partial}{\partial x} ((f (x, y)) (x y - y^{2}))

What is expand 1/2 (e^{4t}+e^{-2t})(6t+1) ?
The solution to expand 1/2 (e^{4t}+e^{-2t})(6t+1) is 3e^{4t}t+1/2 e^{4t}+3e^{-2t}t+1/2 e^{-2t}