What is expand ((1-p)(p+p^2-p^3))/((p+p^2-p^3)) ?

The solution to expand ((1-p)(p+p^2-p^3))/((p+p^2-p^3)) is 1-p

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expand ((1-p)(p+p^2-p^3))/((p+p^2-p^3))

expand

\frac{( 1 - p ) ( p + p ^{2} - p ^{3} )}{( p + p ^{2} - p ^{3} )}

1 - p

Solution steps

\frac{( 1 - p ) ( p + p ^{2} - p ^{3} )}{p + p ^{2} - p ^{3}}

Cancel the common factor:

p + p^{2} - p^{3}

= 1 - p

\frac{x + 1}{( x - 1 ) ( x ^{2} + 1 )}

(2 y y^{'} (x) + 2 y^{'} (x)) (x^{3} + 2 x - 1)

e^{x} (e^{x} - 1)^{2}

\frac{19 ( e ^{2} + 3 )}{3}

\frac{e ^{- s}}{( s - 1 ) ( s - 2 )}

What is expand ((1-p)(p+p^2-p^3))/((p+p^2-p^3)) ?
The solution to expand ((1-p)(p+p^2-p^3))/((p+p^2-p^3)) is 1-p