What is expand (2x^2+2x-3)/((2x+1)^2) ?

The solution to expand (2x^2+2x-3)/((2x+1)^2) is (2x^2+2x-3)/(4x^2+4x+1)

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expand (2x^2+2x-3)/((2x+1)^2)

expand

\frac{2 x ^{2} + 2 x - 3}{( 2 x + 1 ) ^{2}}

\frac{2 x ^{2} + 2 x - 3}{4 x ^{2} + 4 x + 1}

Solution steps

\frac{2 x ^{2} + 2 x - 3}{( 2 x + 1 ) ^{2}}

(2 x + 1)^{2} = 4 x^{2} + 4 x + 1

= \frac{2 x ^{2} + 2 x - 3}{4 x ^{2} + 4 x + 1}

\frac{56 y - 38}{3 ( y - 3 ) ( 5 y - 2 )}

\frac{s}{( s + 1 ) ( s + 2 )}

\frac{1}{5 ( s - 2 )}

\frac{2 x}{( x ^{2} + 4 ) ^{2}}

(x + 2 ux) (u d x + x d u)

What is expand (2x^2+2x-3)/((2x+1)^2) ?
The solution to expand (2x^2+2x-3)/((2x+1)^2) is (2x^2+2x-3)/(4x^2+4x+1)