What is the answer to 2x+(sqrt(2))+3=2 ?

The answer to 2x+(sqrt(2))+3=2 is x=(-1-sqrt(2))/2

Solve for x: 2x+(sqrt(2))+3=2

The solution is x=(-1-sqrt(2))/2

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2 x + (2) + 3 = 2

x = \frac{- 1 - 2}{2}

Decimal Notation

x = - 1.20710 \dots

Solution steps

2 x + (2) + 3 = 2

2 x + 2 + 3 = 2

Move

2

to the right side

2 x + 3 = 2 - 2

Move

3

to the right side

2 x = - 1 - 2

Divide both sides by

2

x = \frac{- 1 - 2}{2}

0.4 (2 x + 8) - 0.4 = 0.2 (4 x - 12) + 6 x

(x - 3) (x + 8) = 0

- 8 x + 4 = 36

j^{2} = 16

9 \geq x^{2}

What is the answer to 2x+(sqrt(2))+3=2 ?
The answer to 2x+(sqrt(2))+3=2 is x=(-1-sqrt(2))/2
Solve for x: 2x+(sqrt(2))+3=2
The solution is x=(-1-sqrt(2))/2