What is expand 1/(x(x+1)(0.01x+1)(0.02x+1)) ?

The solution to expand 1/(x(x+1)(0.01x+1)(0.02x+1)) is 1/(0.0002x^4+0.0302x^3+1.03x^2+x)

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expand 1/(x(x+1)(0.01x+1)(0.02x+1))

expand

\frac{1}{x ( x + 1 ) ( 0.01 x + 1 ) ( 0.02 x + 1 )}

\frac{1}{0.0002 x ^{4} + 0.0302 x ^{3} + 1.03 x ^{2} + x}

Solution steps

\frac{1}{x ( x + 1 ) ( 0.01 x + 1 ) ( 0.02 x + 1 )}

Expand

x (x + 1) (0.01 x + 1) (0.02 x + 1) : 0.0002 x^{4} + 0.0302 x^{3} + 1.03 x^{2} + x

= \frac{1}{0.0002 x ^{4} + 0.0302 x ^{3} + 1.03 x ^{2} + x}

\frac{3 ( a - b )}{5 ( a + b )}

\frac{s - 4}{( s + 1 ) ( s ^{2} + 1 )}

k (\frac{e ^{r t}}{r} + C)

(5 x + 3 e^{y}) d x + 2 x e^{y} d y

\frac{( 3 x + 1 ) ^{\frac{3}{2}} ( 18 x - 4 )}{135}

What is expand 1/(x(x+1)(0.01x+1)(0.02x+1)) ?
The solution to expand 1/(x(x+1)(0.01x+1)(0.02x+1)) is 1/(0.0002x^4+0.0302x^3+1.03x^2+x)