What is expand (a(a-3)^2)/((3a+1)(3a+2)) ?

The solution to expand (a(a-3)^2)/((3a+1)(3a+2)) is (a^3-6a^2+9a)/(9a^2+9a+2)

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expand (a(a-3)^2)/((3a+1)(3a+2))

expand

\frac{a ( a - 3 ) ^{2}}{( 3 a + 1 ) ( 3 a + 2 )}

\frac{a ^{3} - 6 a ^{2} + 9 a}{9 a ^{2} + 9 a + 2}

Solution steps

\frac{a ( a - 3 ) ^{2}}{( 3 a + 1 ) ( 3 a + 2 )}

(a - 3)^{2} = a^{2} - 6 a + 9

= \frac{a ( a ^{2} - 6 a + 9 )}{( 3 a + 1 ) ( 3 a + 2 )}

Expand

(3 a + 1) (3 a + 2) : 9 a^{2} + 9 a + 2

= \frac{a ( a ^{2} - 6 a + 9 )}{9 a ^{2} + 9 a + 2}

Expand

a (a^{2} - 6 a + 9) : a^{3} - 6 a^{2} + 9 a

= \frac{a ^{3} - 6 a ^{2} + 9 a}{9 a ^{2} + 9 a + 2}

\frac{e ^{- 2 π s}}{( s + 1 ) ( s + 3 ) ( s + 4 )}

\frac{2}{5} b y^{3}

\frac{( a - c ^{\frac{1}{g}} ) g}{c ^{\frac{1}{g}}}

\frac{3}{( s ^{2} + 9 ) ( s + 1 ) ( x + 5 )}

\frac{20 x ^{2} - 60 x + 46}{( x + 1 ) ( 2 x - 5 ) ( x - 1 )}

What is expand (a(a-3)^2)/((3a+1)(3a+2)) ?
The solution to expand (a(a-3)^2)/((3a+1)(3a+2)) is (a^3-6a^2+9a)/(9a^2+9a+2)