What is expand-4/((x+1)(x+2)(x-1)) ?

The solution to expand-4/((x+1)(x+2)(x-1)) is -4/(x^3+2x^2-x-2)

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expand-4/((x+1)(x+2)(x-1))

expand

- \frac{4}{( x + 1 ) ( x + 2 ) ( x - 1 )}

- \frac{4}{x ^{3} + 2 x ^{2} - x - 2}

Solution steps

- \frac{4}{( x + 1 ) ( x + 2 ) ( x - 1 )}

Expand

(x + 1) (x + 2) (x - 1) : x^{3} + 2 x^{2} - x - 2

= - \frac{4}{x ^{3} + 2 x ^{2} - x - 2}

\frac{2 - x}{x ^{3} ( x - 3 )}

\frac{2}{( 4 x + 3 ) ( 4 x - 1 )}

\frac{x}{x ^{2} + 1} + \frac{1}{3 x} - \frac{1}{x ^{2}}

\frac{( n + 3 ) ( n + 2 )}{( n + 1 ) ( n + 4 )}

\frac{( 4 - 16 x )}{( 5 - 4 x ) ( 2 x + 3 )}

What is expand-4/((x+1)(x+2)(x-1)) ?
The solution to expand-4/((x+1)(x+2)(x-1)) is -4/(x^3+2x^2-x-2)