What is expand (e^x-1)(e^x+1) ?

The solution to expand (e^x-1)(e^x+1) is e^{2x}-1

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expand (e^x-1)(e^x+1)

expand

(e^{x} - 1) (e^{x} + 1)

e^{2 x} - 1

Solution steps

(e^{x} - 1) (e^{x} + 1)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{x}, b = 1

= (e^{x})^{2} - 1^{2}

Simplify

(e^{x})^{2} - 1^{2} : e^{2 x} - 1

= e^{2 x} - 1

f (t) = 28 (e^{- 0.05 t} - e^{- 0.21 t})

cos (4 t) h (t - \frac{7 π}{4})

lo g_{10} (1000) x^{4} y^{2}

\frac{x ^{3} + 4 ^{3}}{x + 4}

X^{2} - 10 X^{2} - 60

What is expand (e^x-1)(e^x+1) ?
The solution to expand (e^x-1)(e^x+1) is e^{2x}-1