What is expand 1/(s^2(s-3)^2) ?

The solution to expand 1/(s^2(s-3)^2) is 1/(s^4-6s^3+9s^2)

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expand 1/(s^2(s-3)^2)

expand

\frac{1}{s ^{2} ( s - 3 ) ^{2}}

\frac{1}{s ^{4} - 6 s ^{3} + 9 s ^{2}}

Solution steps

\frac{1}{s ^{2} ( s - 3 ) ^{2}}

(s - 3)^{2} = s^{2} - 6 s + 9

= \frac{1}{s ^{2} ( s ^{2} - 6 s + 9 )}

Expand

s^{2} (s^{2} - 6 s + 9) : s^{4} - 6 s^{3} + 9 s^{2}

= \frac{1}{s ^{4} - 6 s ^{3} + 9 s ^{2}}

\frac{( x ^{2} + 3 x + 5 ) ^{n} + x ^{2} ( x + 3 ) ^{2} + 3}{x ^{2} - 3 x + 4}

- \frac{2 x y}{( x ^{2} + y ^{2} ) ^{2}}

\frac{( 1 - 2 x ) π}{x - 1}

\frac{3 ( x + h ) + 4 - 3 x + 4}{h}

f (+ 5, - 1)

What is expand 1/(s^2(s-3)^2) ?
The solution to expand 1/(s^2(s-3)^2) is 1/(s^4-6s^3+9s^2)