What is expand-(x^2(-10x^3+3x^2-60x))/(20) ?

The solution to expand-(x^2(-10x^3+3x^2-60x))/(20) is (x^5)/2-(3x^4)/(20)+3x^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(x^2(-10x^3+3x^2-60x))/(20)

expand

- \frac{x ^{2} ( - 10 x ^{3} + 3 x ^{2} - 60 x )}{20}

\frac{x ^{5}}{2} - \frac{3 x ^{4}}{20} + 3 x^{3}

Solution steps

- \frac{x ^{2} ( - 10 x ^{3} + 3 x ^{2} - 60 x )}{20}

Expand

x^{2} (- 10 x^{3} + 3 x^{2} - 60 x) : - 10 x^{5} + 3 x^{4} - 60 x^{3}

= - \frac{- 10 x ^{5} + 3 x ^{4} - 60 x ^{3}}{20}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 10 x ^{5} + 3 x ^{4} - 60 x ^{3}}{20} = - (- \frac{10 x ^{5}}{20}) - (\frac{3 x ^{4}}{20}) - (- \frac{60 x ^{3}}{20})

= - (- \frac{10 x ^{5}}{20}) - (\frac{3 x ^{4}}{20}) - (- \frac{60 x ^{3}}{20})

Remove parentheses:

(a) = a, - (- a) = a

= \frac{10 x ^{5}}{20} - \frac{3 x ^{4}}{20} + \frac{60 x ^{3}}{20}

Cancel

\frac{10 x ^{5}}{20} : \frac{x ^{5}}{2}

= \frac{x ^{5}}{2} - \frac{3 x ^{4}}{20} + \frac{60 x ^{3}}{20}

Divide the numbers:

\frac{60}{20} = 3

= \frac{x ^{5}}{2} - \frac{3 x ^{4}}{20} + 3 x^{3}

((ln (x) + 1))^{2}

\frac{r ( r - θ )}{θ ^{2}}

\frac{( 124 x + 127 ) ( x - 1 )}{30}

\frac{2 ( x ^{2} + 1 )}{x ^{2} ( x ^{2} + 5 )}

What is expand-(x^2(-10x^3+3x^2-60x))/(20) ?
The solution to expand-(x^2(-10x^3+3x^2-60x))/(20) is (x^5)/2-(3x^4)/(20)+3x^3