What is expand e^x(1-e^{-2x}) ?

The solution to expand e^x(1-e^{-2x}) is e^x-e^{-x}

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expand e^x(1-e^{-2x})

expand

e^{x} (1 - e^{- 2 x})

e^{x} - e^{- x}

Solution steps

e^{x} (1 - e^{- 2 x})

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x}, b = 1, c = e^{- 2 x}

= e^{x} \cdot 1 - e^{x} e^{- 2 x}

= 1 \cdot e^{x} - e^{x} e^{- 2 x}

Simplify

1 \cdot e^{x} - e^{x} e^{- 2 x} : e^{x} - e^{- x}

= e^{x} - e^{- x}

\frac{d ^{2}}{d x ^{2}} ((y) (x^{3} - 3 x^{2} + 3 x))

f (1, - 2) 9 x^{2} y - 4 x y^{2}

x^{2} + y^{2} + (z - 1)^{2}

x (2, 3, 0, - 1) + y (- 5, 4, 3, 2) + z (1, - 2, 2, 5)

\frac{d}{d h} ((V (h)) ((3 h^{2} + 4)^{\frac{3}{2}} - 8))

What is expand e^x(1-e^{-2x}) ?
The solution to expand e^x(1-e^{-2x}) is e^x-e^{-x}