What is expand (x(6x^3+15x-1))/3 ?

The solution to expand (x(6x^3+15x-1))/3 is 2x^4+5x^2-x/3

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expand (x(6x^3+15x-1))/3

expand

\frac{x ( 6 x ^{3} + 15 x - 1 )}{3}

2 x^{4} + 5 x^{2} - \frac{x}{3}

Solution steps

\frac{x ( 6 x ^{3} + 15 x - 1 )}{3}

Expand

x (6 x^{3} + 15 x - 1) : 6 x^{4} + 15 x^{2} - x

= \frac{6 x ^{4} + 15 x ^{2} - x}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{4} + 15 x ^{2} - x}{3} = \frac{6 x ^{4}}{3} + \frac{15 x ^{2}}{3} - \frac{x}{3}

= \frac{6 x ^{4}}{3} + \frac{15 x ^{2}}{3} - \frac{x}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2 x^{4} + \frac{15 x ^{2}}{3} - \frac{x}{3}

Divide the numbers:

\frac{15}{3} = 5

= 2 x^{4} + 5 x^{2} - \frac{x}{3}

\frac{( 90 - 3 x ) ( 5 x + 15 )}{2}

(x + x) d x

lo g_{10} (3) (\frac{x ^{2} y ^{3}}{2 z})

\frac{( 81 x + 6 ) ^{27}}{2187}

\frac{125 - 10 x ^{2}}{( x ^{2} + 25 ) ^{\frac{5}{2}}}

What is expand (x(6x^3+15x-1))/3 ?
The solution to expand (x(6x^3+15x-1))/3 is 2x^4+5x^2-x/3