What is expand 2(x^2+x-2)^2 ?

The solution to expand 2(x^2+x-2)^2 is 2x^4+4x^3-6x^2-8x+8

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expand 2(x^2+x-2)^2

expand

2 (x^{2} + x - 2)^{2}

2 x^{4} + 4 x^{3} - 6 x^{2} - 8 x + 8

Solution steps

2 (x^{2} + x - 2)^{2}

(x^{2} + x - 2)^{2} = x^{4} + 2 x^{3} - 3 x^{2} - 4 x + 4

= 2 (x^{4} + 2 x^{3} - 3 x^{2} - 4 x + 4)

Distribute parentheses

= 2 x^{4} + 2 \cdot 2 x^{3} + 2 (- 3 x^{2}) + 2 (- 4 x) + 2 \cdot 4

Apply minus-plus rules

+ (- a) = - a

= 2 x^{4} + 2 \cdot 2 x^{3} - 2 \cdot 3 x^{2} - 2 \cdot 4 x + 2 \cdot 4

Simplify

2 x^{4} + 2 \cdot 2 x^{3} - 2 \cdot 3 x^{2} - 2 \cdot 4 x + 2 \cdot 4 : 2 x^{4} + 4 x^{3} - 6 x^{2} - 8 x + 8

= 2 x^{4} + 4 x^{3} - 6 x^{2} - 8 x + 8

\frac{9}{( 4 n + 9 ) ( 4 n + 13 )}

\frac{x ^{4} + a x ^{2} + b}{( x - 1 ) ( x - 5 )}

(7 e^{t} cos (t) + 7 e^{t} sin (t))^{2}

[\frac{2 F}{( S - 1 ) ( S + 1 )}] - \frac{1}{S ^{2}}

cos (2) (t - π)

What is expand 2(x^2+x-2)^2 ?
The solution to expand 2(x^2+x-2)^2 is 2x^4+4x^3-6x^2-8x+8