What is expand-2(-2e^{1-x^2}x^2+e^{1-x^2}) ?

The solution to expand-2(-2e^{1-x^2}x^2+e^{1-x^2}) is 4e^{1-x^2}x^2-2e^{1-x^2}

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expand-2(-2e^{1-x^2}x^2+e^{1-x^2})

expand

- 2 (- 2 e^{1 - x^{2}} x^{2} + e^{1 - x^{2}})

4 e^{1 - x^{2}} x^{2} - 2 e^{1 - x^{2}}

Solution steps

- 2 (- 2 e^{1 - x^{2}} x^{2} + e^{1 - x^{2}})

Apply the distributive law:

a (b + c) = ab + a c

a = - 2, b = - 2 e^{1 - x^{2}} x^{2}, c = e^{1 - x^{2}}

= - 2 (- 2 e^{1 - x^{2}} x^{2}) + (- 2) e^{1 - x^{2}}

Apply minus-plus rules

- (- a) = a, + (- a) = - a

= 2 \cdot 2 e^{1 - x^{2}} x^{2} - 2 e^{1 - x^{2}}

Multiply the numbers:

2 \cdot 2 = 4

= 4 e^{1 - x^{2}} x^{2} - 2 e^{1 - x^{2}}

\frac{x - h y \cdot ( y _{2} - y _{3} )}{y _{4} \cdot y _{5}}

- \frac{3}{s ( s - 4 ) ( s + 1 )}

e^{x} \cdot y (x + y + 1)

\frac{1}{( 4 x - 3 ) ( 4 x + 1 )}

(n + 1)!^{2}

What is expand-2(-2e^{1-x^2}x^2+e^{1-x^2}) ?
The solution to expand-2(-2e^{1-x^2}x^2+e^{1-x^2}) is 4e^{1-x^2}x^2-2e^{1-x^2}