What is the d/(dθ)(({x}(θ))(2(1-cos(θ)))) ?

The d/(dθ)(({x}(θ))(2(1-cos(θ)))) is 2(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))

What is the first d/(dθ)(({x}(θ))(2(1-cos(θ)))) ?

The first d/(dθ)(({x}(θ))(2(1-cos(θ)))) is 2(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))

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\frac{d}{d θ} ((x (θ)) (2 (1 - cos (θ))))

2 (\frac{d}{d θ} (x (θ)) (1 - cos (θ)) + sin (θ) x (θ))

Solution steps

\frac{d}{d θ} ((x (θ)) (2 (1 - cos (θ))))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (x (θ) (1 - cos (θ)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x (θ), g = 1 - cos (θ)

= 2 (\frac{d}{d θ} (x (θ)) (1 - cos (θ)) + \frac{d}{d θ} (1 - cos (θ)) x (θ))

\frac{d}{d θ} (1 - cos (θ)) = sin (θ)

= 2 (\frac{d}{d θ} (x (θ)) (1 - cos (θ)) + sin (θ) x (θ))

x^{- \frac{1}{2}} + x^{- \frac{1}{2}}

2 + U (t - \frac{7}{2}) e^{- t} sin (π t)

\frac{1}{( s + 1 ) ( s + 2 ) \cdot e ^{- 2 s - 2}}

\frac{9 x ^{2} + 3 x + 2}{( x ^{2} - 9 ) x}

\frac{5 x}{2 ( 2 x ^{2} + 1 )}

What is the d/(dθ)(({x}(θ))(2(1-cos(θ)))) ?
The d/(dθ)(({x}(θ))(2(1-cos(θ)))) is 2(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))
What is the first d/(dθ)(({x}(θ))(2(1-cos(θ)))) ?
The first d/(dθ)(({x}(θ))(2(1-cos(θ)))) is 2(d/(dθ)({x}(θ))(1-cos(θ))+sin(θ){x}(θ))