What is expand ((3s-1)(3s-2)(s-1))/9 ?

The solution to expand ((3s-1)(3s-2)(s-1))/9 is s^3-2s^2+(11s)/9-2/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((3s-1)(3s-2)(s-1))/9

expand

\frac{( 3 s - 1 ) ( 3 s - 2 ) ( s - 1 )}{9}

s^{3} - 2 s^{2} + \frac{11 s}{9} - \frac{2}{9}

Solution steps

\frac{( 3 s - 1 ) ( 3 s - 2 ) ( s - 1 )}{9}

Expand

(3 s - 1) (3 s - 2) (s - 1) : 9 s^{3} - 18 s^{2} + 11 s - 2

= \frac{9 s ^{3} - 18 s ^{2} + 11 s - 2}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 s ^{3} - 18 s ^{2} + 11 s - 2}{9} = \frac{9 s ^{3}}{9} - \frac{18 s ^{2}}{9} + \frac{11 s}{9} - \frac{2}{9}

= \frac{9 s ^{3}}{9} - \frac{18 s ^{2}}{9} + \frac{11 s}{9} - \frac{2}{9}

Divide the numbers:

\frac{9}{9} = 1

= s^{3} - \frac{18 s ^{2}}{9} + \frac{11 s}{9} - \frac{2}{9}

Divide the numbers:

\frac{18}{9} = 2

= s^{3} - 2 s^{2} + \frac{11 s}{9} - \frac{2}{9}

s^{2} - \frac{3}{2} s - 1

\frac{8 s}{( x + 1 ) ( x - 1 ) ( x ^{2} + 4 x + 5 )}

\frac{x + e ^{x} ( 4 + x ^{2} )}{e ^{x} + 4}

(e^{- 5 t} - e^{2 t})^{2}

\frac{5 a + 5}{4} - \frac{3 - 7 a}{6}

What is expand ((3s-1)(3s-2)(s-1))/9 ?
The solution to expand ((3s-1)(3s-2)(s-1))/9 is s^3-2s^2+(11s)/9-2/9