What is expand 1/4 (1/2 e^{2x}-1/2 e^{-2x}) ?

The solution to expand 1/4 (1/2 e^{2x}-1/2 e^{-2x}) is 1/8 e^{2x}-1/8 e^{-2x}

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expand 1/4 (1/2 e^{2x}-1/2 e^{-2x})

expand

\frac{1}{4} (\frac{1}{2} e^{2 x} - \frac{1}{2} e^{- 2 x})

\frac{1}{8} e^{2 x} - \frac{1}{8} e^{- 2 x}

Solution steps

\frac{1}{4} (\frac{1}{2} e^{2 x} - \frac{1}{2} e^{- 2 x})

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{4}, b = \frac{1}{2} e^{2 x}, c = \frac{1}{2} e^{- 2 x}

= \frac{1}{4} \cdot \frac{1}{2} e^{2 x} - \frac{1}{4} \cdot \frac{1}{2} e^{- 2 x}

Simplify

\frac{1}{4} \cdot \frac{1}{2} e^{2 x} - \frac{1}{4} \cdot \frac{1}{2} e^{- 2 x} : \frac{1}{8} e^{2 x} - \frac{1}{8} e^{- 2 x}

= \frac{1}{8} e^{2 x} - \frac{1}{8} e^{- 2 x}

\frac{( - z - 1 ) ^{3} z}{6}

(x^{'} + h (x))^{2}

\frac{( 2 y - y ^{2} ) ^{3} \cdot y}{3}

(10 - 6 x) e^{x}

\frac{( 2 x ^{3} + 3 x ^{2} + x - 1 )}{( x + 1 ) ( x ^{2} + 2 x + 2 ) ^{2}}

What is expand 1/4 (1/2 e^{2x}-1/2 e^{-2x}) ?
The solution to expand 1/4 (1/2 e^{2x}-1/2 e^{-2x}) is 1/8 e^{2x}-1/8 e^{-2x}