What is expand dx((x^2-3x+2)*(2x^3+1)) ?

The solution to expand dx((x^2-3x+2)*(2x^3+1)) is 2x^5dx+x^2dx-6x^4dx-3xdx+4x^3dx+2dx

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expand dx((x^2-3x+2)*(2x^3+1))

expand

d x ((x^{2} - 3 x + 2) \cdot (2 x^{3} + 1))

2 x^{5} d x + x^{2} d x - 6 x^{4} d x - 3 x d x + 4 x^{3} d x + 2 d x

Solution steps

d x ((x^{2} - 3 x + 2) (2 x^{3} + 1))

Remove parentheses:

(a) = a

= d x (x^{2} - 3 x + 2) (2 x^{3} + 1)

Expand

(x^{2} - 3 x + 2) (2 x^{3} + 1) : 2 x^{5} + x^{2} - 6 x^{4} - 3 x + 4 x^{3} + 2

= d x (2 x^{5} + x^{2} - 6 x^{4} - 3 x + 4 x^{3} + 2)

Expand

d x (2 x^{5} + x^{2} - 6 x^{4} - 3 x + 4 x^{3} + 2) : 2 x^{5} d x + x^{2} d x - 6 x^{4} d x - 3 x d x + 4 x^{3} d x + 2 d x

= 2 x^{5} d x + x^{2} d x - 6 x^{4} d x - 3 x d x + 4 x^{3} d x + 2 d x

\frac{k}{( s - 3 ) ( s + 11 )}

\frac{\partial}{\partial x} ((y) (3 x^{2} + y^{2} x + y))

(\frac{( e ^{x} + e ^{(- x)} )}{( 2 )})^{2}

e^{x (x - 3)}

\frac{6 x}{( 5 + 3 x ^{2} ) ^{4}}

What is expand dx((x^2-3x+2)*(2x^3+1)) ?
The solution to expand dx((x^2-3x+2)*(2x^3+1)) is 2x^5dx+x^2dx-6x^4dx-3xdx+4x^3dx+2dx