What is expand (c(-2bd+2bc+d^2-c^2))/(2d) ?

The solution to expand (c(-2bd+2bc+d^2-c^2))/(2d) is -cb+(c^2b)/d+(cd)/2-(c^3)/(2d)

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expand (c(-2bd+2bc+d^2-c^2))/(2d)

expand

\frac{c ( - 2 b d + 2 b c + d ^{2} - c ^{2} )}{2 d}

- c b + \frac{c ^{2} b}{d} + \frac{c d}{2} - \frac{c ^{3}}{2 d}

Solution steps

\frac{c ( - 2 b d + 2 b c + d ^{2} - c ^{2} )}{2 d}

Expand

c (- 2 b d + 2 b c + d^{2} - c^{2}) : - 2 c b d + 2 c^{2} b + c d^{2} - c^{3}

= \frac{- 2 c b d + 2 c ^{2} b + c d ^{2} - c ^{3}}{2 d}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 c b d + 2 c ^{2} b + c d ^{2} - c ^{3}}{2 d} = - \frac{2 c b d}{2 d} + \frac{2 c ^{2} b}{2 d} + \frac{c d ^{2}}{2 d} - \frac{c ^{3}}{2 d}

= - \frac{2 c b d}{2 d} + \frac{2 c ^{2} b}{2 d} + \frac{c d ^{2}}{2 d} - \frac{c ^{3}}{2 d}

Cancel

\frac{2 c b d}{2 d} : c b

= - c b + \frac{2 c ^{2} b}{2 d} + \frac{c d ^{2}}{2 d} - \frac{c ^{3}}{2 d}

Divide the numbers:

\frac{2}{2} = 1

= - c b + \frac{c ^{2} b}{d} + \frac{c d ^{2}}{2 d} - \frac{c ^{3}}{2 d}

Cancel

\frac{c d ^{2}}{2 d} : \frac{c d}{2}

= - c b + \frac{c ^{2} b}{d} + \frac{c d}{2} - \frac{c ^{3}}{2 d}

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x^{'} + y (y - 3)

\frac{x ^{2} - 2 x - 2}{x ( x - 1 ) ( x + 2 )}

\frac{10 x ( 10 - x - x ^{1.5} )}{10 - x}

What is expand (c(-2bd+2bc+d^2-c^2))/(2d) ?
The solution to expand (c(-2bd+2bc+d^2-c^2))/(2d) is -cb+(c^2b)/d+(cd)/2-(c^3)/(2d)