What is expand (u^3(12-17z^5))/(4z^3) ?

The solution to expand (u^3(12-17z^5))/(4z^3) is (3u^3}{z^3}-\frac{17u^3z^2)/4

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expand (u^3(12-17z^5))/(4z^3)

expand

\frac{u ^{3} ( 12 - 17 z ^{5} )}{4 z ^{3}}

\frac{3 u ^{3}}{z ^{3}} - \frac{17 u ^{3} z ^{2}}{4}

Solution steps

\frac{u ^{3} ( 12 - 17 z ^{5} )}{4 z ^{3}}

Expand

u^{3} (12 - 17 z^{5}) : 12 u^{3} - 17 u^{3} z^{5}

= \frac{12 u ^{3} - 17 u ^{3} z ^{5}}{4 z ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 u ^{3} - 17 u ^{3} z ^{5}}{4 z ^{3}} = \frac{12 u ^{3}}{4 z ^{3}} - \frac{17 u ^{3} z ^{5}}{4 z ^{3}}

= \frac{12 u ^{3}}{4 z ^{3}} - \frac{17 u ^{3} z ^{5}}{4 z ^{3}}

Divide the numbers:

\frac{12}{4} = 3

= \frac{3 u ^{3}}{z ^{3}} - \frac{17 u ^{3} z ^{5}}{4 z ^{3}}

Cancel

\frac{17 u ^{3} z ^{5}}{4 z ^{3}} : \frac{17 u ^{3} z ^{2}}{4}

= \frac{3 u ^{3}}{z ^{3}} - \frac{17 u ^{3} z ^{2}}{4}

((x + 3) - (e^{\frac{2 x}{3}}))^{2}

2 (e^{x} + 1) e^{x}

\frac{\partial}{\partial x} ((1 - y)^{3} \cdot x^{2}) + y^{2}

\frac{1}{( 1 + x ^{4} ) ^{2}}

\frac{x ^{3} + 48 x ^{2} + 65 x - 240}{( x - 8 ) ( x ^{2} + 5 )}

What is expand (u^3(12-17z^5))/(4z^3) ?
The solution to expand (u^3(12-17z^5))/(4z^3) is (3u^3}{z^3}-\frac{17u^3z^2)/4