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Popular >

expand 4(2e^{x^2+2y+z^2}x^2+e^{x^2+2y+z^2})

Solution

expand

4 (2 e^{x^{2} + 2 y + z^{2}} x^{2} + e^{x^{2} + 2 y + z^{2}})

Solution

8 e^{x^{2} + 2 y + z^{2}} x^{2} + 4 e^{x^{2} + 2 y + z^{2}}

Solution steps

4 (2 e^{x^{2} + 2 y + z^{2}} x^{2} + e^{x^{2} + 2 y + z^{2}})

Apply the distributive law:

a (b + c) = ab + a c

a = 4, b = 2 e^{x^{2} + 2 y + z^{2}} x^{2}, c = e^{x^{2} + 2 y + z^{2}}

= 4 \cdot 2 e^{x^{2} + 2 y + z^{2}} x^{2} + 4 e^{x^{2} + 2 y + z^{2}}

Multiply the numbers:

4 \cdot 2 = 8

= 8 e^{x^{2} + 2 y + z^{2}} x^{2} + 4 e^{x^{2} + 2 y + z^{2}}

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Frequently Asked Questions (FAQ)

What is expand 4(2e^{x^2+2y+z^2}x^2+e^{x^2+2y+z^2}) ?
The solution to expand 4(2e^{x^2+2y+z^2}x^2+e^{x^2+2y+z^2}) is 8e^{x^2+2y+z^2}x^2+4e^{x^2+2y+z^2}