What is the d/(dt)((x)(x^3-3xy+y^3)) ?

The d/(dt)((x)(x^3-3xy+y^3)) is 0

What is the first d/(dt)((x)(x^3-3xy+y^3)) ?

The first d/(dt)((x)(x^3-3xy+y^3)) is 0

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\frac{d}{d t} ((x) (x^{3} - 3 x y + y^{3}))

0

Solution steps

\frac{d}{d t} ((x) (x^{3} - 3 x y + y^{3}))

Treat

x, y

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

π (\frac{x ^{2}}{4} - \frac{ln ( x )}{2})

\frac{- n + ( - 1 ) ^{n}}{n}

(2 x + 4 x^{3}) d x

\frac{( 3 x ^{3} + 2 )}{( x - 1 ) ( x ^{2} + 9 )}

a (1, 1) + b (0, - 2)

What is the d/(dt)((x)(x^3-3xy+y^3)) ?
The d/(dt)((x)(x^3-3xy+y^3)) is 0
What is the first d/(dt)((x)(x^3-3xy+y^3)) ?
The first d/(dt)((x)(x^3-3xy+y^3)) is 0