What is expand ((3x+4)(2x+5))/2 ?

The solution to expand ((3x+4)(2x+5))/2 is 3x^2+(23x)/2+10

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expand ((3x+4)(2x+5))/2

expand

\frac{( 3 x + 4 ) ( 2 x + 5 )}{2}

3 x^{2} + \frac{23 x}{2} + 10

Solution steps

\frac{( 3 x + 4 ) ( 2 x + 5 )}{2}

Expand

(3 x + 4) (2 x + 5) : 6 x^{2} + 23 x + 20

= \frac{6 x ^{2} + 23 x + 20}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 23 x + 20}{2} = \frac{6 x ^{2}}{2} + \frac{23 x}{2} + \frac{20}{2}

= \frac{6 x ^{2}}{2} + \frac{23 x}{2} + \frac{20}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3 x^{2} + \frac{23 x}{2} + \frac{20}{2}

Divide the numbers:

\frac{20}{2} = 10

= 3 x^{2} + \frac{23 x}{2} + 10

\frac{x - 4}{10 ( x - 2 )}

\frac{2 x ^{3} + 10 x}{( x ^{2} + 1 ) ^{2}}

\frac{12 x ^{6} - 96 x ^{4} + 34 x ^{3} - 3}{( 3 x - 4 x ^{4} ) ^{2}}

\frac{35 ( x - 3 ) x}{4}

4^{0}

What is expand ((3x+4)(2x+5))/2 ?
The solution to expand ((3x+4)(2x+5))/2 is 3x^2+(23x)/2+10