What is expand (2(x^2-1))/(x^2-3) ?

The solution to expand (2(x^2-1))/(x^2-3) is (2x^2-2)/(x^2-3)

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expand (2(x^2-1))/(x^2-3)

expand

\frac{2 ( x ^{2} - 1 )}{x ^{2} - 3}

\frac{2 x ^{2} - 2}{x ^{2} - 3}

Solution steps

\frac{2 ( x ^{2} - 1 )}{x ^{2} - 3}

Expand

2 (x^{2} - 1) : 2 x^{2} - 2

= \frac{2 x ^{2} - 2}{x ^{2} - 3}

\frac{4 a x}{( x + a ) ^{2} ( x - a ) ^{2}}

\frac{( x - 7 ) ^{2} ( m x - 7 m )}{( x - 7 ) ^{3} + ( m x - 7 m ) ^{2}}

\frac{d}{d t} ((r (t, y, x)) (y + x cos (t)))

\frac{9}{x ( x + 6 )}

\frac{( 5 x - 5 )}{5} \cdot \frac{( x + 10 )}{( x - 1 )}

What is expand (2(x^2-1))/(x^2-3) ?
The solution to expand (2(x^2-1))/(x^2-3) is (2x^2-2)/(x^2-3)