What is expand (7(3-3z)^2)/2 ?

The solution to expand (7(3-3z)^2)/2 is (63z^2)/2-63z+63/2

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expand (7(3-3z)^2)/2

expand

\frac{7 ( 3 - 3 z ) ^{2}}{2}

\frac{63 z ^{2}}{2} - 63 z + \frac{63}{2}

Solution steps

\frac{7 ( 3 - 3 z ) ^{2}}{2}

(3 - 3 z)^{2} = 9 - 18 z + 9 z^{2}

= \frac{7 ( 9 z ^{2} - 18 z + 9 )}{2}

Expand

7 (9 - 18 z + 9 z^{2}) : 63 - 126 z + 63 z^{2}

= \frac{63 - 126 z + 63 z ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{63 - 126 z + 63 z ^{2}}{2} = \frac{63}{2} - \frac{126 z}{2} + \frac{63 z ^{2}}{2}

= \frac{63}{2} - \frac{126 z}{2} + \frac{63 z ^{2}}{2}

Divide the numbers:

\frac{126}{2} = 63

= \frac{63}{2} - 63 z + \frac{63 z ^{2}}{2}

Rewrite in standard form

= \frac{63 z ^{2}}{2} - 63 z + \frac{63}{2}

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What is expand (7(3-3z)^2)/2 ?
The solution to expand (7(3-3z)^2)/2 is (63z^2)/2-63z+63/2