What is expand 3i^{40}-5i^{15}-i^8 ?

The solution to expand 3i^{40}-5i^{15}-i^8 is 2+5i

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expand 3i^{40}-5i^{15}-i^8

expand

3 i^{40} - 5 i^{15} - i^{8}

2 + 5 i

Solution steps

3 i^{40} - 5 i^{15} - i^{8}

3 i^{40} = 3

5 i^{15} = - 5 i

i^{8} = 1

= 3 - (- 5 i) - 1

Apply rule

- (- a) = a

= 3 + 5 i - 1

Subtract the numbers:

3 - 1 = 2

= 2 + 5 i

\frac{( x - 3 )}{( x - 2 ) \cdot ( x + 1 )}

- (3 + h + 1)^{\frac{1}{2}} + (3 + 1)^{\frac{1}{2}}

4 (1 - e^{- 2 x})

(x + h)^{2} + 4

(2 m + 7) (2 m - 7)^{'}

What is expand 3i^{40}-5i^{15}-i^8 ?
The solution to expand 3i^{40}-5i^{15}-i^8 is 2+5i