What is expand 2(cos(2t)-sin(2t)+e^{-2t}) ?

The solution to expand 2(cos(2t)-sin(2t)+e^{-2t}) is 2cos(2t)-2sin(2t)+2e^{-2t}

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expand 2(cos(2t)-sin(2t)+e^{-2t})

expand

2 (cos (2 t) - sin (2 t) + e^{- 2 t})

2 cos (2 t) - 2 sin (2 t) + 2 e^{- 2 t}

Solution steps

2 (cos (2 t) - sin (2 t) + e^{- 2 t})

Distribute parentheses

= 2 cos (2 t) + 2 (- sin (2 t)) + 2 e^{- 2 t}

Apply minus-plus rules

+ (- a) = - a

= 2 cos (2 t) - 2 sin (2 t) + 2 e^{- 2 t}

\frac{2}{( 2 \cdot s + 1 ) ( s + 1 )}

\frac{d}{d x} (((x^{2} + 4)^{8}) 12 (x^{2} + 3)^{4}) + (11 x^{2} + 3)

4^{8}

d s (s - 1)^{3}

\frac{( ln ( x ) + 1 ) ( 1 - ln ( x ) ) + ln ( x )}{( 1 - ln ( x ) ) ^{2}}

What is expand 2(cos(2t)-sin(2t)+e^{-2t}) ?
The solution to expand 2(cos(2t)-sin(2t)+e^{-2t}) is 2cos(2t)-2sin(2t)+2e^{-2t}