What is expand f(-4e^x+|x|-1/8)dx ?

The solution to expand f(-4e^x+|x|-1/8)dx is -4e^xfdx+f|x|dx-(fdx)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand f(-4e^x+|x|-1/8)dx

expand

f (- 4 e^{x} + ∣ x ∣ - \frac{1}{8}) d x

- 4 e^{x} fd x + f ∣ x ∣ d x - \frac{fd x}{8}

Solution steps

f (- 4 e^{x} + ∣ x ∣ - \frac{1}{8}) d x

Distribute parentheses

= fd x (- 4 e^{x}) + fd x ∣ x ∣ + fd x (- \frac{1}{8})

Apply minus-plus rules

+ (- a) = - a

= - 4 e^{x} fd x + f ∣ x ∣ d x - \frac{1}{8} fd x

\frac{1}{8} fd x = \frac{fd x}{8}

= - 4 e^{x} fd x + f ∣ x ∣ d x - \frac{fd x}{8}

\frac{5 x ^{2} - 7 x}{( x + 1 ) ( x - 3 )}

\frac{x ^{3} - 2 x ^{2}}{( x - 1 ) ^{2}}

(y^{2} + 3 y + 1) d x + 8

\frac{1}{4} \cdot (e^{a x} + e^{- a x}) (e^{b x} + e^{- b x})

\frac{( 9.5939 ( s + 10 ) )}{( ( s + 95.94 ) )}

What is expand f(-4e^x+|x|-1/8)dx ?
The solution to expand f(-4e^x+|x|-1/8)dx is -4e^xfdx+f|x|dx-(fdx)/8