What is (\partial)/(\partial x)((z)(e^{7z}-xyz)) ?

The answer to (\partial)/(\partial x)((z)(e^{7z}-xyz)) is -z^2y

Popular >

(\partial)/(\partial x)((z)(e^{7z}-xyz))

\frac{\partial}{\partial x} ((z) (e^{7 z} - x yz))

- z^{2} y

Solution steps

\frac{\partial}{\partial x} ((z) (e^{7 z} - x yz))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (e^{7 z} - x yz)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial x} (e^{7 z}) - \frac{\partial}{\partial x} (x yz))

\frac{\partial}{\partial x} (e^{7 z}) = 0

\frac{\partial}{\partial x} (x yz) = zy

= z (0 - zy)

Simplify

z (0 - zy) : - z^{2} y

= - z^{2} y

cos ((1 - t^{6}) \cdot (t^{4} - 2 t)^{2})

(2 x + 5) e^{(x)}

\frac{( p x ^{2} + r + b x ) ( - k - m x ^{2} - b x - r )}{r + b x}

\frac{4 x ^{3} + 9 x ^{2} - 17 x - 5}{( 2 x - 3 ) ( x ^{2} + 1 )}

\frac{θ + α θ ^{2} - α ^{2} θ ^{3}}{( 1 - α θ ) ^{3}}

What is (\partial)/(\partial x)((z)(e^{7z}-xyz)) ?
The answer to (\partial)/(\partial x)((z)(e^{7z}-xyz)) is -z^2y