What is expand (2l((-1)^n-1))/(pi^2n^2) ?

The solution to expand (2l((-1)^n-1))/(pi^2n^2) is (2(-1)^nl)/(pi^2n^2)-(2l)/(pi^2n^2)

Popular >

expand (2l((-1)^n-1))/(pi^2n^2)

expand

\frac{2 l ( ( - 1 ) ^{n} - 1 )}{π ^{2} n ^{2}}

\frac{2 ( - 1 ) ^{n} l}{π ^{2} n ^{2}} - \frac{2 l}{π ^{2} n ^{2}}

Solution steps

\frac{2 l ( ( - 1 ) ^{n} - 1 )}{π ^{2} n ^{2}}

Expand

2 l ((- 1)^{n} - 1) : 2 (- 1)^{n} l - 2 l

= \frac{2 ( - 1 ) ^{n} l - 2 l}{π ^{2} n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 ( - 1 ) ^{n} l - 2 l}{π ^{2} n ^{2}} = \frac{2 ( - 1 ) ^{n} l}{π ^{2} n ^{2}} - \frac{2 l}{π ^{2} n ^{2}}

= \frac{2 ( - 1 ) ^{n} l}{π ^{2} n ^{2}} - \frac{2 l}{π ^{2} n ^{2}}

y + \frac{x}{2} + \frac{3}{2}

4 r^{2} - r^{2} (33 - π)

b (a + b + c)^{3}

(x e^{x}) (1 + e^{x})

e^{(1 - x^{2} - y^{2})} - 2 e^{(1 - x^{2} - y^{2})} x (x + y)

What is expand (2l((-1)^n-1))/(pi^2n^2) ?
The solution to expand (2l((-1)^n-1))/(pi^2n^2) is (2(-1)^nl)/(pi^2n^2)-(2l)/(pi^2n^2)