What is expand (7x)/((2x+1)(x-3)dx) ?

The solution to expand (7x)/((2x+1)(x-3)dx) is (7x)/(2x^2dx-5xdx-3dx)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (7x)/((2x+1)(x-3)dx)

expand

\frac{7 x}{( 2 x + 1 ) ( x - 3 ) d x}

\frac{7 x}{2 x ^{2} d x - 5 x d x - 3 d x}

Solution steps

\frac{7 x}{( 2 x + 1 ) ( x - 3 ) d x}

Expand

(2 x + 1) (x - 3) d x : 2 x^{2} d x - 5 x d x - 3 d x

= \frac{7 x}{2 x ^{2} d x - 5 x d x - 3 d x}

(e - 4)^{2}

\frac{12 ( x - 2 ) ^{2}}{6 ( x - 2 ) x + 5}

\frac{( 9 x ^{2} ( x + 1 ) ^{2} )}{4} - (\frac{3 n ( n + 1 )}{2})

\frac{( x + 2 ) ( x - 2 )}{( x - 4 ) ( x + 1 )}

\frac{4 ( 3 ^{n} + 2 ^{n} )}{( 3. 3 ^{n} + 2. 2 ^{n} )}

What is expand (7x)/((2x+1)(x-3)dx) ?
The solution to expand (7x)/((2x+1)(x-3)dx) is (7x)/(2x^2dx-5xdx-3dx)